What is (\partial)/(\partial x)(x^3-6xy+y^3) ?

The answer to (\partial)/(\partial x)(x^3-6xy+y^3) is 3x^2-6y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^3-6xy+y^3)

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3})

3 x^{2} - 6 y

Solution steps

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (6 x y) + \frac{\partial}{\partial x} (y^{3})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (6 x y) = 6 y

\frac{\partial}{\partial x} (y^{3}) = 0

= 3 x^{2} - 6 y + 0

Simplify

= 3 x^{2} - 6 y

\frac{\partial}{\partial z} (z^{3} - x^{2} y)

y^{^{'}} = \frac{2 t}{y + t ^{2} y}

\int x ln (2 x - 3) d x

\int \frac{1}{x ^{2} + 10 x + 25} d x

n \to \infty lim (\frac{1}{n !})

What is (\partial)/(\partial x)(x^3-6xy+y^3) ?
The answer to (\partial)/(\partial x)(x^3-6xy+y^3) is 3x^2-6y