What is the tangent of y=tan(x),(pi/4 ,1) ?

The tangent of y=tan(x),(pi/4 ,1) is y=2x+1-pi/2

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tangent of y=tan(x),(pi/4 ,1)

tangent of

y = tan (x), (\frac{π}{4}, 1)

y = 2 x + 1 - \frac{π}{2}

Solution steps

Find the slope of

y = tan (x) : \frac{d y}{d x} = sec^{2} (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 1) : y = 2 x + 1 - \frac{π}{2}

y = 2 x + 1 - \frac{π}{2}

\int_{8}^{12} \frac{2}{x ^{3}} d x

\int (x ln (x))^{2} d x

\frac{\partial}{\partial x} (y e^{y})

\frac{\partial}{\partial x} (5 x y^{3} + 15 x y - 4 y^{2})

\frac{d}{d x} (x^{2} \cdot y^{3})

What is the tangent of y=tan(x),(pi/4 ,1) ?
The tangent of y=tan(x),(pi/4 ,1) is y=2x+1-pi/2