What is the derivative of 64sin(2x) ?

The derivative of 64sin(2x) is 128cos(2x)

What is the first derivative of 64sin(2x) ?

The first derivative of 64sin(2x) is 128cos(2x)

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\frac{d}{d x} (64 sin (2 x))

128 cos (2 x)

Solution steps

\frac{d}{d x} (64 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 64 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 64 cos (2 x) \cdot 2

Simplify

= 128 cos (2 x)

\frac{d}{d x} (sec^{9} (2^{x}))

x^{- 8}

\frac{\partial}{\partial x} (e^{(3 x + 5 y)})

\frac{d}{d x} (x \cdot e^{x} + e^{x})

What is the derivative of 64sin(2x) ?
The derivative of 64sin(2x) is 128cos(2x)
What is the first derivative of 64sin(2x) ?
The first derivative of 64sin(2x) is 128cos(2x)