en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=5(x^3-x),y=0

Solution

area

y = 5 (x^{3} - x), y = 0

Solution

\frac{5}{2}

+1

Decimal Notation

2.5

Solution steps

Apply the area formula:

\int_{- 1}^{1} 5 x^{3} - x d x

Solve

\int_{- 1}^{1} 5 x^{3} - x d x : \frac{5}{2}

The area is:

= \frac{5}{2}

Popular Examples

derivative of x^2(x+1)^3 derivative of

x^{2} (x + 1)^{3}

(dx)/(dt)=6-(3x)/(500),x(0)=0

\frac{d x}{d t} = 6 - \frac{3 x}{500}, x (0) = 0

tangent of x/(x^2+1)tangent of

\frac{x}{x ^{2} + 1}

tangent of f(x)=x^2-1,\at x=-1 tangent of

f (x) = x^{2} - 1, at x = - 1

inverse oflaplace 6/((s^2+9)^2)inverse laplace

\frac{6}{( s ^{2} + 9 ) ^{2}}

Frequently Asked Questions (FAQ)

What is area y=5(x^3-x),y=0 ?
The answer to area y=5(x^3-x),y=0 is 5/2