What is the derivative of 6e^x+8/(\sqrt[3]{x)} ?

The derivative of 6e^x+8/(\sqrt[3]{x)} is 6e^x-8/(3x^{4/3)}

What is the first derivative of 6e^x+8/(\sqrt[3]{x)} ?

The first derivative of 6e^x+8/(\sqrt[3]{x)} is 6e^x-8/(3x^{4/3)}

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derivative of

6 e^{x} + \frac{8}{3 x}

6 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (6 e^{x} + \frac{8}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x}) + \frac{d}{d x} (\frac{8}{3 x})

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

\frac{d}{d x} (\frac{8}{3 x}) = - \frac{8}{3 x ^{\frac{4}{3}}}

= 6 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

x \to 2 + lim (\frac{7}{x - 2})

\frac{d y}{d x} + (\frac{7}{x}) y = x + 2

\int_{- 2}^{3} \frac{1}{1 + 9 t ^{2}} d t

\int \frac{x}{1 + 4 x} d x

x^{2} - 2 (- 4.14)

What is the derivative of 6e^x+8/(\sqrt[3]{x)} ?
The derivative of 6e^x+8/(\sqrt[3]{x)} is 6e^x-8/(3x^{4/3)}
What is the first derivative of 6e^x+8/(\sqrt[3]{x)} ?
The first derivative of 6e^x+8/(\sqrt[3]{x)} is 6e^x-8/(3x^{4/3)}