What is the integral from 0 to pi of 3sin(x) ?

The integral from 0 to pi of 3sin(x) is 6

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integral from 0 to pi of 3sin(x)

\int_{0}^{π} 3 sin (x) d x

6

Solution steps

\int_{0}^{π} 3 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 3 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

\int_{1}^{6} π (x - 1) d x

\frac{d r}{d t} = 6 (t + 1)^{\frac{1}{2}}, r (0) = 0

(3.6) (5.1)

f (x) = 2 e^{x}

2 x^{3} - x^{2} + 2 (1.3)

What is the integral from 0 to pi of 3sin(x) ?
The integral from 0 to pi of 3sin(x) is 6