What is (\partial)/(\partial y)(y-3/x+1) ?

The answer to (\partial)/(\partial y)(y-3/x+1) is 1

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(\partial)/(\partial y)(y-3/x+1)

\frac{\partial}{\partial y} (y - \frac{3}{x} + 1)

1

Solution steps

\frac{\partial}{\partial y} (y - \frac{3}{x} + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (\frac{3}{x}) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (\frac{3}{x}) = 0

\frac{\partial}{\partial y} (1) = 0

= 1 - 0 + 0

Simplify

= 1

\int \frac{1}{x ( x ^{2} - 1 ) ^{\frac{3}{2}}} d x

6 e^{x} (cos (x) - sin (x))

\int_{7}^{14} 196 - x^{2} d x

\int \frac{1}{3} e^{x + 3} + \frac{3}{x} - 5 d x

y^{^{'}} = \frac{y ^{2}}{x y + y ^{2}}

What is (\partial)/(\partial y)(y-3/x+1) ?
The answer to (\partial)/(\partial y)(y-3/x+1) is 1