What is the derivative of (x-2^4-1) ?

The derivative of (x-2^4-1) is 4x^3-24x^2+48x-32

What is the first derivative of (x-2^4-1) ?

The first derivative of (x-2^4-1) is 4x^3-24x^2+48x-32

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\frac{d}{d x} ((x - 2)^{4} - 1)

4 x^{3} - 24 x^{2} + 48 x - 32

Solution steps

\frac{d}{d x} ((x - 2)^{4} - 1)

Simplify

(x - 2)^{4} - 1 : x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 15

= \frac{d}{d x} (x^{4} - 8 x^{3} + 24 x^{2} - 32 x + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (8 x^{3}) + \frac{d}{d x} (24 x^{2}) - \frac{d}{d x} (32 x) + \frac{d}{d x} (15)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (24 x^{2}) = 48 x

\frac{d}{d x} (32 x) = 32

\frac{d}{d x} (15) = 0

= 4 x^{3} - 24 x^{2} + 48 x - 32 + 0

Simplify

= 4 x^{3} - 24 x^{2} + 48 x - 32

\int x I n (1 + x)

(- 6, 7), (1, - 12)

\int_{0}^{4} \frac{8 t}{( t - 5 ) ^{2}} d t

x \to 0 lim (\frac{∣ x - 0 ∣}{x - 0})

What is the derivative of (x-2^4-1) ?
The derivative of (x-2^4-1) is 4x^3-24x^2+48x-32
What is the first derivative of (x-2^4-1) ?
The first derivative of (x-2^4-1) is 4x^3-24x^2+48x-32