What is the tangent of f(x)= 2/x ,(-8,-1/4) ?

The tangent of f(x)= 2/x ,(-8,-1/4) is y=-1/32 x-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 2/x ,(-8,-1/4)

tangent of

f (x) = \frac{2}{x}, (- 8, - \frac{1}{4})

y = - \frac{1}{32} x - \frac{1}{2}

Solution steps

Find the slope of

f (x) = \frac{2}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

f (x) = \frac{2}{x}

(- 8, - \frac{1}{4}) : m = - \frac{1}{32}

Find the line with slope m=

- \frac{1}{32}

and passing through

(- 8, - \frac{1}{4}) : y = - \frac{1}{32} x - \frac{1}{2}

y = - \frac{1}{32} x - \frac{1}{2}

\frac{8 x}{1 - tan ( x )}

\frac{d}{d x} (\frac{1 - x}{x})

\frac{\partial}{\partial y} (\frac{x - y}{x + 2 y})

\frac{\partial}{\partial x} (y^{4} sin (4 x))

y^{^{''}} y^{^{'}} = 2

What is the tangent of f(x)= 2/x ,(-8,-1/4) ?
The tangent of f(x)= 2/x ,(-8,-1/4) is y=-1/32 x-1/2