What is the derivative of g(x)=2(4-7x)^4 ?

The derivative of g(x)=2(4-7x)^4 is -56(4-7x)^3

What is the first derivative of g(x)=2(4-7x)^4 ?

The first derivative of g(x)=2(4-7x)^4 is -56(4-7x)^3

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derivative of

g (x) = 2 (4 - 7 x)^{4}

- 56 (4 - 7 x)^{3}

Solution steps

\frac{d}{d x} (2 (4 - 7 x)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} ((4 - 7 x)^{4})

Apply the chain rule:

4 (4 - 7 x)^{3} \frac{d}{d x} (4 - 7 x)

= 4 (4 - 7 x)^{3} \frac{d}{d x} (4 - 7 x)

\frac{d}{d x} (4 - 7 x) = - 7

= 2 \cdot 4 (4 - 7 x)^{3} (- 7)

Simplify

= - 56 (4 - 7 x)^{3}

\int \frac{sin ( 3 x )}{cos ( 3 x ) + 1} d x

\int_{0}^{1} 2 x e^{x} d x

\int \frac{cos ^{2} ( x )}{1 + sin ( x )} d x

\int \frac{x}{( 3 x ^{2} + 8 ) ^{2}} d x

f (x) = ln (x + 3)

What is the derivative of g(x)=2(4-7x)^4 ?
The derivative of g(x)=2(4-7x)^4 is -56(4-7x)^3
What is the first derivative of g(x)=2(4-7x)^4 ?
The first derivative of g(x)=2(4-7x)^4 is -56(4-7x)^3