What is the solution for f^'(x)=cos(cos(x)) ?

The solution for f^'(x)=cos(cos(x)) is f(x)=integral of cos(cos(x))

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f^'(x)=cos(cos(x))

f^{^{'}} (x) = cos (cos (x))

f (x) = \int cos (cos (x)) d x

Solution steps

f^{'} (x) = cos (cos (x))

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int cos (cos (x)) d x

f (x) = \int cos (cos (x)) d x

n = 0 \sum \infty n + 1 (\frac{1}{9})^{n}

\frac{\partial}{\partial x} (3 x^{2} \cdot cos^{2} (x - y))

\int x (2 x^{2} - 4)^{3} d x

x \to 8 + lim (\frac{6 x}{x - 8})

\frac{d}{d x} (3 x^{5 x})

What is the solution for f^'(x)=cos(cos(x)) ?
The solution for f^'(x)=cos(cos(x)) is f(x)=integral of cos(cos(x))