What is the integral from 0 to 2 of 3^x ?

The integral from 0 to 2 of 3^x is 8/(ln(3))

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integral from 0 to 2 of 3^x

\int_{0}^{2} 3^{x} d x

\frac{8}{ln ( 3 )}

Decimal Notation

7.28191 \dots

Solution steps

\int_{0}^{2} 3^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{3 ^{x}}{ln ( 3 )}]_{0}^{2}

Compute the boundaries:

\frac{8}{ln ( 3 )}

= \frac{8}{ln ( 3 )}

arctan (2 x)

\frac{\partial}{\partial y} (\frac{x}{x ^{3} - y ^{7}})

\int \frac{( x ^{2} + x - 1 )}{x ^{2} - x} d x

f (t) = \frac{cos ( t )}{t}

\frac{\frac{1}{x ^{2}} d u}{d x} - \frac{2 u}{x ^{3}} = - \frac{1}{x ^{2}}

What is the integral from 0 to 2 of 3^x ?
The integral from 0 to 2 of 3^x is 8/(ln(3))