What is the tangent of r=3+2sin(θ) ?

The tangent of r=3+2sin(θ) is r=2cos(a_{0})θ+3+2sin(a_{0})-2cos(a_{0})a_{0}

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tangent of r=3+2sin(θ)

tangent of

r = 3 + 2 sin (θ)

r = 2 cos (a_{0}) θ + 3 + 2 sin (a_{0}) - 2 cos (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

θ = a_{0}

Find the tangent point:

(a_{0}, 3 + 2 sin (a_{0}))

Find the slope of

r = 3 + 2 sin (θ) : \frac{d r}{d θ} = 2 cos (θ)

Compute the slope of

r = 3 + 2 sin (θ)

θ = a_{0} : m = 2 cos (a_{0})

Find the line with slope m=

2 cos (a_{0})

and passing through

(a_{0}, 3 + 2 sin (a_{0})) : r = 2 cos (a_{0}) θ + 3 + 2 sin (a_{0}) - 2 cos (a_{0}) a_{0}

r = 2 cos (a_{0}) θ + 3 + 2 sin (a_{0}) - 2 cos (a_{0}) a_{0}

y = x x

f (x) = - 5 x^{2}, at a = 4

y^{^{''}} - (\frac{2}{x}) y^{^{'}} - (\frac{7}{x ^{2}}) y = 0

x \to 1 lim (51 - 2 x)

\frac{d}{d x} (ln (sec (x^{2})))

What is the tangent of r=3+2sin(θ) ?
The tangent of r=3+2sin(θ) is r=2cos(a_{0})θ+3+2sin(a_{0})-2cos(a_{0})a_{0}