What is the integral of x^{3/4}y^3 ?

The integral of x^{3/4}y^3 is (x^{3/4}y^4)/4+C

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integral of x^{3/4}y^3

\int x^{\frac{3}{4}} y^{3} d y

\frac{x ^{\frac{3}{4}} y ^{4}}{4} + C

Solution steps

\int x^{\frac{3}{4}} y^{3} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x^{\frac{3}{4}} \cdot \int y^{3} d y

Apply the Power Rule

: \frac{y ^{4}}{4}

= x^{\frac{3}{4}} \frac{y ^{4}}{4}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{\frac{3}{4}} y ^{4}}{4}

Add a constant to the solution

= \frac{x ^{\frac{3}{4}} y ^{4}}{4} + C

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What is the integral of x^{3/4}y^3 ?
The integral of x^{3/4}y^3 is (x^{3/4}y^4)/4+C