What is derivative of f(x)=e^{arctan(2t^2)} ?

The answer to derivative of f(x)=e^{arctan(2t^2)} is (dt)/(dx)=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of f(x)=e^{arctan(2t^2)}

derivative of

f (x) = e^{a r c t a n (2 t^{2})}

\frac{d t}{d x} = 0

Solution steps

f (x) = e^{a r c t a n (2 t^{2})}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{4 e ^{a r c t a n (2 t^{2})} t \frac{d t}{d x}}{4 t ^{4} + 1}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int x^{2} (2 x^{3} + 3)^{4} d x

\int \frac{x + 9}{9 - 3 x - 2 x ^{2}} d x

x \to 0 lim ((1 + \frac{3}{x ^{2}})^{x})

y^{^{''}} + b^{2} y = 0

y^{^{'}} = \frac{( e ^{x - y} )}{1 + e ^{x}}

What is derivative of f(x)=e^{arctan(2t^2)} ?
The answer to derivative of f(x)=e^{arctan(2t^2)} is (dt)/(dx)=0