What is the integral from 0 to 1 of 2pi(x+11)(x^2) ?

The integral from 0 to 1 of 2pi(x+11)(x^2) is (47pi)/6

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integral from 0 to 1 of 2pi(x+11)(x^2)

\int_{0}^{1} 2 π (x + 11) (x^{2}) d x

\frac{47 π}{6}

Decimal Notation

24.60914 \dots

Solution steps

\int_{0}^{1} 2 π (x + 11) x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int_{0}^{1} (x + 11) x^{2} d x

Expand

(x + 11) x^{2} : x^{3} + 11 x^{2}

= 2 π \cdot \int_{0}^{1} x^{3} + 11 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 π (\int_{0}^{1} x^{3} d x + \int_{0}^{1} 11 x^{2} d x)

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 11 x^{2} d x = \frac{11}{3}

= 2 π (\frac{1}{4} + \frac{11}{3})

Simplify

2 π (\frac{1}{4} + \frac{11}{3}) : \frac{47 π}{6}

= \frac{47 π}{6}

\int \frac{arctan ( x )}{x ^{2}} d x

\frac{d}{d x} (\frac{x + 1}{( x - 1 ) ^{2}})

\int \frac{x}{x ^{2} + 36} d x

\frac{\partial}{\partial x} ((3 + x^{2} - 3 y^{2})^{\frac{1}{2}})

2 x (\frac{d y}{d x}) - 10 y = x^{- 6}

What is the integral from 0 to 1 of 2pi(x+11)(x^2) ?
The integral from 0 to 1 of 2pi(x+11)(x^2) is (47pi)/6