What is the solution for (1+e^{2x})y^2dy=e^xdx,y(0)=0 ?

The solution for (1+e^{2x})y^2dy=e^xdx,y(0)=0 is y=\sqrt[3]{3arctan(e^x)+c_{1}}

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(1+e^{2x})y^2dy=e^xdx,y(0)=0

(1 + e^{2 x}) y^{2} d y = e^{x} d x, y (0) = 0

Solution steps

(1 + e^{2 x}) y^{2} d y = e^{x} d x

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What is the solution for (1+e^{2x})y^2dy=e^xdx,y(0)=0 ?
The solution for (1+e^{2x})y^2dy=e^xdx,y(0)=0 is y=\sqrt[3]{3arctan(e^x)+c_{1}}