What is the integral of sin(x)2x ?

The integral of sin(x)2x is 2(-xcos(x)+sin(x))+C

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integral of sin(x)2x

\int sin (x) 2 x d x

2 (- x cos (x) + sin (x)) + C

Solution steps

\int sin (x) \cdot 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (x) x d x

Apply Integration By Parts

: - x cos (x) - \int - cos (x) d x

= 2 (- x cos (x) - \int - cos (x) d x)

\int - cos (x) d x = - sin (x)

= 2 (- x cos (x) - (- sin (x)))

Simplify

= 2 (- x cos (x) + sin (x))

Add a constant to the solution

= 2 (- x cos (x) + sin (x)) + C

x \to \infty lim (\frac{( x ^{2} )}{e ^{x^{2}}})

n = 0 \sum \infty \frac{1 ^{n}}{3 ^{n}}

\int - \frac{4 x + 10}{x ^{3}} d x

x \to 0 - lim (\frac{4}{tan ( x )})

\int e^{- s t} \cdot t d t

What is the integral of sin(x)2x ?
The integral of sin(x)2x is 2(-xcos(x)+sin(x))+C