What is the derivative of 9arcsec(x) ?

The derivative of 9arcsec(x) is 9/(sqrt(x^2)\sqrt{x^2-1)}

What is the first derivative of 9arcsec(x) ?

The first derivative of 9arcsec(x) is 9/(sqrt(x^2)\sqrt{x^2-1)}

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derivative of

9 arcsec (x)

\frac{9}{x ^{2} x ^{2} - 1}

Solution steps

\frac{d}{d x} (9 arcsec (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (arcsec (x))

Apply the common derivative:

\frac{d}{d x} (arcsec (x)) = \frac{1}{x ^{2} x ^{2} - 1}

= 9 \cdot \frac{1}{x ^{2} x ^{2} - 1}

Simplify

9 \cdot \frac{1}{x ^{2} x ^{2} - 1} : \frac{9}{x ^{2} x ^{2} - 1}

= \frac{9}{x ^{2} x ^{2} - 1}

\frac{\partial}{\partial y} (x y (\frac{1}{y ^{3}} + 2))

\int \frac{1}{4} e^{4 x + 1} d x

- x^{2} + 80 x - 600

sin^{2} (π x)

\int \frac{24 x - 2 x ^{3}}{x ^{4} - 16} d x

What is the derivative of 9arcsec(x) ?
The derivative of 9arcsec(x) is 9/(sqrt(x^2)\sqrt{x^2-1)}
What is the first derivative of 9arcsec(x) ?
The first derivative of 9arcsec(x) is 9/(sqrt(x^2)\sqrt{x^2-1)}