What is maclaurin x/(2x+1) ?

The answer to maclaurin x/(2x+1) is x-2x^2+4x^3-8x^4+16x^5+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

maclaurin x/(2x+1)

maclaurin

\frac{x}{2 x + 1}

x - 2 x^{2} + 4 x^{3} - 8 x^{4} + 16 x^{5} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( \frac{x}{2 x + 1} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{x}{2 x + 1} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{x}{2 x + 1} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{1}{1 !} x + \frac{- 4}{2 !} x^{2} + \frac{24}{3 !} x^{3} + \frac{- 192}{4 !} x^{4} + \frac{1920}{5 !} x^{5} + \dots

Refine

= x - 2 x^{2} + 4 x^{3} - 8 x^{4} + 16 x^{5} + \dots

\int e^{(x + y)}

x y^{2} y^{^{'}} = x + 8

\int \frac{2 x}{4 x ^{4} - 9} d x

\int (6 x + 1) (6 x^{2} + 2 x)^{\frac{3}{4}} d x

What is maclaurin x/(2x+1) ?
The answer to maclaurin x/(2x+1) is x-2x^2+4x^3-8x^4+16x^5+\ldots