What is the integral of (tan^2(x))/(cos^2(x)) ?

The integral of (tan^2(x))/(cos^2(x)) is (tan^3(x))/3+C

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integral of (tan^2(x))/(cos^2(x))

\int \frac{tan ^{2} ( x )}{cos ^{2} ( x )} d x

\frac{tan ^{3} ( x )}{3} + C

Solution steps

\int \frac{tan ^{2} ( x )}{cos ^{2} ( x )} d x

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = tan (x)

= \frac{tan ^{3} ( x )}{3}

Add a constant to the solution

= \frac{tan ^{3} ( x )}{3} + C

f (x) = 3 x^{3}, (- 1, - 3)

\frac{d}{d x} (x e - x)

\frac{d}{d x} (e^{π})

y = - 8 - (\frac{x}{7})^{\frac{5}{2}}

\frac{d}{d x} (4^{3 s i n (x) - e^{x}})

What is the integral of (tan^2(x))/(cos^2(x)) ?
The integral of (tan^2(x))/(cos^2(x)) is (tan^3(x))/3+C