What is the derivative of 5/(4x-3) ?

The derivative of 5/(4x-3) is -(20)/((4x-3)^2)

What is the first derivative of 5/(4x-3) ?

The first derivative of 5/(4x-3) is -(20)/((4x-3)^2)

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\frac{d}{d x} (\frac{5}{4 x - 3})

- \frac{20}{( 4 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{4 x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{4 x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((4 x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x - 3 ) ^{2}} \frac{d}{d x} (4 x - 3)

= - \frac{1}{( 4 x - 3 ) ^{2}} \frac{d}{d x} (4 x - 3)

\frac{d}{d x} (4 x - 3) = 4

= 5 (- \frac{1}{( 4 x - 3 ) ^{2}} \cdot 4)

Simplify

5 (- \frac{1}{( 4 x - 3 ) ^{2}} \cdot 4) : - \frac{20}{( 4 x - 3 ) ^{2}}

= - \frac{20}{( 4 x - 3 ) ^{2}}

\int 2 (sin (x) - cos (x) + 1) d x

tan (5 x)

\int \frac{cos ( 4 x )}{2} d x

\int sec (x) tan (x) (\frac{x}{π}) d x

\frac{d y}{d t} + y = cos (2 t), y (0) = 5

What is the derivative of 5/(4x-3) ?
The derivative of 5/(4x-3) is -(20)/((4x-3)^2)
What is the first derivative of 5/(4x-3) ?
The first derivative of 5/(4x-3) is -(20)/((4x-3)^2)