What is the integral of 3/(x^{1/2)} ?

The integral of 3/(x^{1/2)} is 6x^{1/2}+C

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integral of 3/(x^{1/2)}

\int \frac{3}{x ^{\frac{1}{2}}} d x

6 x^{\frac{1}{2}} + C

Solution steps

\int \frac{3}{x ^{\frac{1}{2}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 3 \cdot 2 x^{\frac{1}{2}}

Simplify

= 6 x^{\frac{1}{2}}

Add a constant to the solution

= 6 x^{\frac{1}{2}} + C

n = 0 \sum \infty 2

\int_{0}^{2} \frac{8 t}{( t - 3 ) ^{2}} d t

\frac{d}{d x} (\frac{x - 1}{3})

\frac{6 x}{x ^{2} + 1} (1.3)

\frac{7 x}{( x ^{3} - 2 ) ^{2}}