What is the derivative of (x^2-2^3) ?

The derivative of (x^2-2^3) is 6x(x^2-2)^2

What is the first derivative of (x^2-2^3) ?

The first derivative of (x^2-2^3) is 6x(x^2-2)^2

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\frac{d}{d x} ((x^{2} - 2)^{3})

6 x (x^{2} - 2)^{2}

Solution steps

\frac{d}{d x} ((x^{2} - 2)^{3})

Apply the chain rule:

3 (x^{2} - 2)^{2} \frac{d}{d x} (x^{2} - 2)

= 3 (x^{2} - 2)^{2} \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 3 (x^{2} - 2)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} - 2)^{2}

\int 5 x^{- 1} d x

\frac{d}{d x} (\frac{1 + x}{x ^{3}})

\frac{\partial}{\partial x} (x y e^{y})

y^{^{'}} + 7 y = e^{6 x}

What is the derivative of (x^2-2^3) ?
The derivative of (x^2-2^3) is 6x(x^2-2)^2
What is the first derivative of (x^2-2^3) ?
The first derivative of (x^2-2^3) is 6x(x^2-2)^2