What is the integral of 4sec^2(2x)tan(2x) ?

The integral of 4sec^2(2x)tan(2x) is tan^2(2x)+C

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integral of 4sec^2(2x)tan(2x)

\int 4 sec^{2} (2 x) tan (2 x) d x

tan^{2} (2 x) + C

Solution steps

\int 4 sec^{2} (2 x) tan (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sec^{2} (2 x) tan (2 x) d x

Apply u-substitution

: \int \frac{u}{2} d u

= 4 \cdot \int \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= 4 \cdot \frac{1}{2} \cdot \frac{u ^{2}}{2}

Substitute back

u = tan (2 x)

= 4 \cdot \frac{1}{2} \cdot \frac{tan ^{2} ( 2 x )}{2}

Simplify

4 \cdot \frac{1}{2} \cdot \frac{tan ^{2} ( 2 x )}{2} : tan^{2} (2 x)

= tan^{2} (2 x)

Add a constant to the solution

= tan^{2} (2 x) + C

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What is the integral of 4sec^2(2x)tan(2x) ?
The integral of 4sec^2(2x)tan(2x) is tan^2(2x)+C