What is the derivative of r(t)-4tan(5t^3) ?

The derivative of r(t)-4tan(5t^3) is t

What is the first derivative of r(t)-4tan(5t^3) ?

The first derivative of r(t)-4tan(5t^3) is t

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derivative of

r (t) - 4 tan (5 t^{3})

t

Solution steps

\frac{d}{d r} (r t - 4 tan (5 t^{3}))

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (r t) - \frac{d}{d r} (4 tan (5 t^{3}))

\frac{d}{d r} (r t) = t

\frac{d}{d r} (4 tan (5 t^{3})) = 0

= t - 0

Simplify

= t

x \to 2 lim (\frac{( 1 )}{( x + 2 )})

y = x^{2} sin (4 x)

f (x) = x^{2} + x, at x = 4

y^{^{''}} + 4 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\frac{d}{d x} (\frac{- 6 x}{x ^{2} + 1})

What is the derivative of r(t)-4tan(5t^3) ?
The derivative of r(t)-4tan(5t^3) is t
What is the first derivative of r(t)-4tan(5t^3) ?
The first derivative of r(t)-4tan(5t^3) is t