What is area f(x)=sqrt(x),g(x)=-sqrt(x),x=1,x=4 ?

The answer to area f(x)=sqrt(x),g(x)=-sqrt(x),x=1,x=4 is 28/3

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area f(x)=sqrt(x),g(x)=-sqrt(x),x=1,x=4

area

f (x) = x, g (x) = - x, x = 1, x = 4

\frac{28}{3}

Decimal Notation

9.33333 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} 2 x d x

Solve

\int_{1}^{4} 2 x d x : \frac{28}{3}

The area is:

= \frac{28}{3}

\frac{d}{d x} (4 sin (x) + 4 cos (x))

1 - 49 x^{2} arccos (7 x)

x \to 2 lim (7 (x) + 10)

f (x) = 2 x^{4}, x = - 2

What is area f(x)=sqrt(x),g(x)=-sqrt(x),x=1,x=4 ?
The answer to area f(x)=sqrt(x),g(x)=-sqrt(x),x=1,x=4 is 28/3