What is the sum from n=1 to infinity of (3n)/(10n+3) ?

The sum from n=1 to infinity of (3n)/(10n+3) is diverges

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sum from n=1 to infinity of (3n)/(10n+3)

n = 1 \sum \infty \frac{3 n}{10 n + 3}

diverges

Solution steps

n = 1 \sum \infty \frac{3 n}{10 n + 3}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 1 \sum \infty \frac{n}{10 n + 3}

Apply Series Divergence Test:

diverges

= 3 diverges

= diverges

n = 5 \sum \infty e^{7} - 6 n

7 t \frac{d y}{d t} + y = t^{5}

\int x^{2} I n (4 x) d x

f (x) = x^{\frac{4}{5}}

What is the sum from n=1 to infinity of (3n)/(10n+3) ?
The sum from n=1 to infinity of (3n)/(10n+3) is diverges