What is the solution for (1+ln(x)+y/x)dx=(9-ln(x))dy ?

The solution for (1+ln(x)+y/x)dx=(9-ln(x))dy is y=(xln(x))/(9-ln(x))+(c_{1})/(9-ln(x))

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(1+ln(x)+y/x)dx=(9-ln(x))dy

(1 + ln (x) + \frac{y}{x}) d x = (9 - ln (x)) d y

y = \frac{x ln ( x )}{9 - ln ( x )} + \frac{c _{1}}{9 - ln ( x )}

Solution steps

(1 + ln (x) + \frac{y}{x}) d x = (9 - ln (x)) d y

Solve linear ODE:

y = \frac{x ln ( x )}{9 - ln ( x )} + \frac{c _{1}}{9 - ln ( x )}

y = \frac{x ln ( x )}{9 - ln ( x )} + \frac{c _{1}}{9 - ln ( x )}

\frac{\partial}{\partial x} (x^{8} e^{x y})

\int 4 x^{2} e^{- 2 x} d x

\frac{\partial}{\partial x} (x^{- 2} \cdot \frac{y}{x ^{3}})

y y^{^{'}} + x y^{2} = x y^{4}

\frac{d}{d x} (\frac{1}{2} x^{- 2})

What is the solution for (1+ln(x)+y/x)dx=(9-ln(x))dy ?
The solution for (1+ln(x)+y/x)dx=(9-ln(x))dy is y=(xln(x))/(9-ln(x))+(c_{1})/(9-ln(x))