What is the derivative of f(x)=x+3/(x^2) ?

The derivative of f(x)=x+3/(x^2) is 1-6/(x^3)

What is the first derivative of f(x)=x+3/(x^2) ?

The first derivative of f(x)=x+3/(x^2) is 1-6/(x^3)

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derivative of

f (x) = x + \frac{3}{x ^{2}}

1 - \frac{6}{x ^{3}}

Solution steps

\frac{d}{d x} (x + \frac{3}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{3}{x ^{2}})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

= 1 - \frac{6}{x ^{3}}

\frac{d}{d x} (2 x sin (π x))

y^{^{''}} - (3 + π) y^{^{'}} + 3 π \cdot y = sin (\frac{π}{2})

(x^{2} - 9) y^{^{'}} + 6 y = (x + 3)^{2}

x \cdot sin (x^{2})

x^{2} + x y - y^{2} = 19, (4, 1)

What is the derivative of f(x)=x+3/(x^2) ?
The derivative of f(x)=x+3/(x^2) is 1-6/(x^3)
What is the first derivative of f(x)=x+3/(x^2) ?
The first derivative of f(x)=x+3/(x^2) is 1-6/(x^3)