What is the derivative of x^2-4x+8 ?

The derivative of x^2-4x+8 is 2x-4

What is the first derivative of x^2-4x+8 ?

The first derivative of x^2-4x+8 is 2x-4

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derivative of

x^{2} - 4 x + 8

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (8) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\frac{s + 1}{s ^{2} + 3 s}

x \cdot \frac{d y}{d x} - y = 3 x^{6} y, y (1) = 2

\int_{2}^{7} 2 π y (7 - y) d y

\int \frac{1}{9 - 7 x} d x

\frac{\partial}{\partial x} (\frac{1}{x ^{3} + 4 x ^{2}})

What is the derivative of x^2-4x+8 ?
The derivative of x^2-4x+8 is 2x-4
What is the first derivative of x^2-4x+8 ?
The first derivative of x^2-4x+8 is 2x-4