What is the derivative of 2x^3y+1 ?

The derivative of 2x^3y+1 is 2(x^3(dy)/(dx)+3x^2y)

What is the first derivative of 2x^3y+1 ?

The first derivative of 2x^3y+1 is 2(x^3(dy)/(dx)+3x^2y)

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\frac{d}{d x} (2 x^{3} y + 1)

2 (x^{3} \frac{d y}{d x} + 3 x^{2} y)

Solution steps

\frac{d}{d x} (2 x^{3} y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3} y) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{3} y) = 2 (3 x^{2} y + \frac{d y}{d x} x^{3})

\frac{d}{d x} (1) = 0

= 2 (3 x^{2} y + \frac{d y}{d x} x^{3}) + 0

Simplify

= 2 (x^{3} \frac{d y}{d x} + 3 x^{2} y)

(3, - 7), (- 10, - 2)

e^{13 x}

\int_{1}^{7} t^{2} - 4 t - 12 d t

\frac{d}{d t} (cosh^{2} (t))

\frac{d y}{d x} = \frac{y ^{2} + 2 x x ^{2} + y ^{2}}{x y}

What is the derivative of 2x^3y+1 ?
The derivative of 2x^3y+1 is 2(x^3(dy)/(dx)+3x^2y)
What is the first derivative of 2x^3y+1 ?
The first derivative of 2x^3y+1 is 2(x^3(dy)/(dx)+3x^2y)