What is the tangent of f(x)=e^{x^7},(-1, 1/e) ?

The tangent of f(x)=e^{x^7},(-1, 1/e) is y= 7/e x+8/e

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tangent of f(x)=e^{x^7},(-1, 1/e)

tangent of

f (x) = e^{x^{7}}, (- 1, \frac{1}{e})

y = \frac{7}{e} x + \frac{8}{e}

Solution steps

Find the slope of

f (x) = e^{x^{7}} : \frac{df ( x )}{d x} = e^{x^{7}} \cdot 7 x^{6}

Compute the slope of

f (x) = e^{x^{7}}

(- 1, \frac{1}{e}) : m = \frac{7}{e}

Find the line with slope m=

\frac{7}{e}

and passing through

(- 1, \frac{1}{e}) : y = \frac{7}{e} x + \frac{8}{e}

y = \frac{7}{e} x + \frac{8}{e}

\frac{d}{d x} (\frac{x ^{2} cos ( e ^{x} )}{( 2 x + 1 ) ^{3}})

\int_{0}^{\frac{π}{2}} 7 cos^{5} (x) d x

\int x^{3} x^{2} - 49 d x

\frac{d}{d x} (ln (1 0^{x}))

y = - x^{2} + 8 x, y = x^{2} - 4 x

What is the tangent of f(x)=e^{x^7},(-1, 1/e) ?
The tangent of f(x)=e^{x^7},(-1, 1/e) is y= 7/e x+8/e