What is the limit as x approaches 0+of x^{x^x} ?

The limit as x approaches 0+of x^{x^x} is 0

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limit as x approaches 0+of x^{x^x}

x \to 0 + lim (x^{x^{x}})

0

Solution steps

x \to 0 + lim (x^{x^{x}})

Apply exponent rules

= x \to 0 + lim (e^{x^{x} l n (x)})

Apply the Limit Chain Rule:

0

= 0

\frac{d}{d x} (x - 0.8 - 0.2 sin (x))

n = 0 \sum \infty \frac{1}{n ^{2} + 4 n + 3}

y = 2 x^{3} - x^{2} + 5, (2, 17)

f (x) = 3 x^{2} + 4 x + 1, at x = 0

8 cos^{2} (y) d x + csc^{2} (x) d y = 0, y (\frac{π}{12}) = \frac{π}{4}

What is the limit as x approaches 0+of x^{x^x} ?
The limit as x approaches 0+of x^{x^x} is 0