What is the derivative of sqrt(2x^2+1) ?

The derivative of sqrt(2x^2+1) is (2x)/(sqrt(2x^2+1))

What is the first derivative of sqrt(2x^2+1) ?

The first derivative of sqrt(2x^2+1) is (2x)/(sqrt(2x^2+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x^{2} + 1)

\frac{2 x}{2 x ^{2} + 1}

Solution steps

\frac{d}{d x} (2 x^{2} + 1)

Apply the chain rule:

\frac{1}{2 2 x ^{2} + 1} \frac{d}{d x} (2 x^{2} + 1)

= \frac{1}{2 2 x ^{2} + 1} \frac{d}{d x} (2 x^{2} + 1)

\frac{d}{d x} (2 x^{2} + 1) = 4 x

= \frac{1}{2 2 x ^{2} + 1} \cdot 4 x

Simplify

\frac{1}{2 2 x ^{2} + 1} \cdot 4 x : \frac{2 x}{2 x ^{2} + 1}

= \frac{2 x}{2 x ^{2} + 1}

\int \frac{( 1 - x )}{e ^{x}} k d x

x \to 0 lim (+ (ln (x)))

y^{^{''}} - 8 y^{^{'}} - 15 y = 0

\frac{2 x}{5}

x \to 2 lim (3 x^{2} + 4 x - 3)

What is the derivative of sqrt(2x^2+1) ?
The derivative of sqrt(2x^2+1) is (2x)/(sqrt(2x^2+1))
What is the first derivative of sqrt(2x^2+1) ?
The first derivative of sqrt(2x^2+1) is (2x)/(sqrt(2x^2+1))