What is the derivative of a^2x^2+b^2 ?

The derivative of a^2x^2+b^2 is 2a^2x

What is the first derivative of a^2x^2+b^2 ?

The first derivative of a^2x^2+b^2 is 2a^2x

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derivative of

a^{2} x^{2} + b^{2}

2 a^{2} x

Solution steps

\frac{d}{d x} (a^{2} x^{2} + b^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{2} x^{2}) + \frac{d}{d x} (b^{2})

\frac{d}{d x} (a^{2} x^{2}) = 2 a^{2} x

\frac{d}{d x} (b^{2}) = 0

= 2 a^{2} x + 0

Simplify

= 2 a^{2} x

y = (\frac{( x ^{2} + 8 )}{x ^{2} - 8})

3 t^{2} + 13 t + 13

e^{\frac{( x ^{5} )}{5}}

\frac{1}{( 1 - t ^{2} ) ^{\frac{1}{2}}}

f (x) = (\frac{x + 1}{x + 3})^{2}, at x = - 2

What is the derivative of a^2x^2+b^2 ?
The derivative of a^2x^2+b^2 is 2a^2x
What is the first derivative of a^2x^2+b^2 ?
The first derivative of a^2x^2+b^2 is 2a^2x