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Popular >

area y=x^2-4x,y=2x+7

Solution

area

y = x^{2} - 4 x, y = 2 x + 7

Solution

\frac{256}{3}

+1

Decimal Notation

85.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{7} x^{2} - 4 x - (2 x + 7) d x

Solve

\int_{- 1}^{7} x^{2} - 4 x - (2 x + 7) d x : \frac{256}{3}

The area is:

= \frac{256}{3}

Popular Examples

(dy)/(dx)=(x^3-y^3)/(3xy^2)

\frac{d y}{d x} = \frac{x ^{3} - y ^{3}}{3 x y ^{2}}

integral of 3ln(x^2-x+4)

\int 3 ln (x^{2} - x + 4) d x

((x-2)^2(x+4))^'

((x - 2)^{2} (x + 4))^{^{'}}

sum from n=1 to infinity of n/(3^{n^2)}

n = 1 \sum \infty \frac{n}{3 ^{n^{2}}}

f(x)=5x^2e^{3x}

f (x) = 5 x^{2} e^{3 x}

Frequently Asked Questions (FAQ)

What is area y=x^2-4x,y=2x+7 ?
The answer to area y=x^2-4x,y=2x+7 is 256/3