What is the limit as x approaches 0 of (1/x+1)^x ?

The limit as x approaches 0 of (1/x+1)^x is Does not exist

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limit as x approaches 0 of (1/x+1)^x

x \to 0 lim ((\frac{1}{x} + 1)^{x})

Does not exist

Solution steps

x \to 0 lim ((\frac{1}{x} + 1)^{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((\frac{1}{x} + 1)^{x}) = 1

x \to 0 - lim ((\frac{1}{x} + 1)^{x}) =

Does not exist

= Does not exist

p (x) = 0.7 x + 20, p (x) = \frac{547.8}{x + 15}

\frac{5}{s ^{2} + 3 s + 2}

x \to - 5 lim (\frac{2 x ^{2} + 7 x - 15}{x ^{2} - 25})

\frac{d y}{d x} = \frac{4 sec ( y )}{( x + 3 ) ^{2}}

\int \frac{1}{4 x ^{2} + 9} d x

What is the limit as x approaches 0 of (1/x+1)^x ?
The limit as x approaches 0 of (1/x+1)^x is Does not exist