What is laplacetransform 5sin(t) ?

The answer to laplacetransform 5sin(t) is 5/(s^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 5sin(t)

laplace transform

5 sin (t)

\frac{5}{s ^{2} + 1}

Solution steps

L {5 sin (t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (t)}

L {sin (t)} : \frac{1}{s ^{2} + 1}

= 5 \cdot \frac{1}{s ^{2} + 1}

Refine

5 \frac{1}{s ^{2} + 1} : \frac{5}{s ^{2} + 1}

= \frac{5}{s ^{2} + 1}

\int_{0}^{1} \frac{1}{e ^{x} + 1} d x

a y^{^{'}} = b x - b y

\frac{d y}{d x} + (5 x) y = 3 x + 5

\int e^{t} + e^{- t} d t

\frac{\partial}{\partial z} (sin (x y))

What is laplacetransform 5sin(t) ?
The answer to laplacetransform 5sin(t) is 5/(s^2+1)