What is the integral from 4 to infinity of 7e^{-x/2} ?

The integral from 4 to infinity of 7e^{-x/2} is (14)/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 4 to infinity of 7e^{-x/2}

\int_{4}^{\infty} 7 e^{- \frac{x}{2}} d x

\frac{14}{e ^{2}}

Decimal Notation

1.89469 \dots

Solution steps

\int_{4}^{\infty} 7 e^{- \frac{x}{2}} d x

Compute the indefinite integral:

\int 7 e^{- \frac{x}{2}} d x = - 14 e^{- \frac{x}{2}} + C

Compute the boundaries:

\int_{4}^{\infty} 7 e^{- \frac{x}{2}} d x = 0 - (- \frac{14}{e ^{2}})

= 0 - (- \frac{14}{e ^{2}})

Simplify

= \frac{14}{e ^{2}}

\frac{d}{d x} (4^{- x^{2}})

\frac{d}{d x} (4 cos (2 x))

\frac{d}{d x} (x^{2} (x - y)^{2}) = x^{2} - y^{2}

(\frac{1}{3 x})^{^{'}}

\frac{d}{d x} ((2 - x)^{\frac{1}{2}})

What is the integral from 4 to infinity of 7e^{-x/2} ?
The integral from 4 to infinity of 7e^{-x/2} is (14)/(e^2)