What is the tangent of 6sqrt(x)-3x ?

The tangent of 6sqrt(x)-3x is y=(3/(sqrt(a_{0))}-3)x+3sqrt(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 6sqrt(x)-3x

tangent of

6 x - 3 x

y = (\frac{3}{a _{0}} - 3) x + 3 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0} - 3 a_{0})

Find the slope of

y = 6 x - 3 x : \frac{d y}{d x} = \frac{3}{x} - 3

Compute the slope of

y = 6 x - 3 x

x = a_{0} : m = \frac{3}{a _{0}} - 3

Find the line with slope m=

\frac{3}{a _{0}} - 3

and passing through

(a_{0}, 6 a_{0} - 3 a_{0}) : y = (\frac{3}{a _{0}} - 3) x + 3 a_{0}

y = (\frac{3}{a _{0}} - 3) x + 3 a_{0}

\int \frac{16 x ^{3} - 4 x}{2 x ^{4} - x ^{2} + 3} d x

x \to 0 lim (sin (\frac{3}{x}))

\int 5 e^{6 x} d x

\int (10 - 5 x) d x

x^{2} y^{^{''}} + 3 x y^{^{'}} + 5 y = 0

What is the tangent of 6sqrt(x)-3x ?
The tangent of 6sqrt(x)-3x is y=(3/(sqrt(a_{0))}-3)x+3sqrt(a_{0)}