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Popular >

integral from 0 to 2 of x+1

Solution

\int_{0}^{2} x + 1 d x

Solution

4

Solution steps

\int_{0}^{2} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= 2 + 2

Simplify

= 4

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t (e^{t} + e^{2 t})^{2}

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\frac{d}{d x} (0.5 e^{\frac{x}{3}} - sin (x))

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\int_{0}^{4} x - 2 x d x

integral of-xsqrt(x-1)

\int - x x - 1 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of x+1 ?
The integral from 0 to 2 of x+1 is 4