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Popular >

y^'+2xy=x^3

Solution

y^{^{'}} + 2 x y = x^{3}

Solution

y = \frac{x ^{2} - 1}{2} + \frac{c _{1}}{e ^{x^{2}}}

Solution steps

y^{'} (x) + 2 x y = x^{3}

Solve linear ODE:

y = \frac{x ^{2} - 1}{2} + \frac{c _{1}}{e ^{x^{2}}}

y = \frac{x ^{2} - 1}{2} + \frac{c _{1}}{e ^{x^{2}}}

Popular Examples

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\frac{d}{d x} (x (x^{2} - 4))

tangent of f(x)=x^3+2x,\at x=0 tangent of

f (x) = x^{3} + 2 x, at x = 0

(\partial)/(\partial x)(8xy+2x^4+2y^4)

\frac{\partial}{\partial x} (8 x y + 2 x^{4} + 2 y^{4})

derivative of sin^{n-2}(x)

\frac{d}{d x} (sin^{n - 2} (x))

Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=x^3 ?
The solution for y^'+2xy=x^3 is y=(x^2-1)/2+(c_{1})/(e^{x^2)}