What is the derivative of sqrt(r)+\sqrt[9]{r} ?

The derivative of sqrt(r)+\sqrt[9]{r} is 1/(2sqrt(r))+1/(9r^{8/9)}

What is the first derivative of sqrt(r)+\sqrt[9]{r} ?

The first derivative of sqrt(r)+\sqrt[9]{r} is 1/(2sqrt(r))+1/(9r^{8/9)}

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derivative of

\frac{1}{2 r} + \frac{1}{9 r ^{\frac{8}{9}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d r} (r) = \frac{1}{2 r}

= \frac{1}{2 r} + \frac{1}{9 r ^{\frac{8}{9}}}

x \to 1 lim (2 x^{2} - x)

x \to - 1 lim (\frac{3 - 4 x}{x})

5^{2 y}

\frac{d y}{d x} = x^{4} (y - 2)

x \to 1 lim (cos (x π))

What is the derivative of sqrt(r)+\sqrt[9]{r} ?
The derivative of sqrt(r)+\sqrt[9]{r} is 1/(2sqrt(r))+1/(9r^{8/9)}
What is the first derivative of sqrt(r)+\sqrt[9]{r} ?
The first derivative of sqrt(r)+\sqrt[9]{r} is 1/(2sqrt(r))+1/(9r^{8/9)}