What is the solution for xy^'-2y=-2x^2+x-2 ?

The solution for xy^'-2y=-2x^2+x-2 is y=-2x^2ln(x)-x+1+c_{1}x^2

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xy^'-2y=-2x^2+x-2

x y^{^{'}} - 2 y = - 2 x^{2} + x - 2

y = - 2 x^{2} ln (x) - x + 1 + c_{1} x^{2}

Solution steps

x y^{'} (x) - 2 y = - 2 x^{2} + x - 2

Solve linear ODE:

y = - 2 x^{2} ln (x) - x + 1 + c_{1} x^{2}

y = - 2 x^{2} ln (x) - x + 1 + c_{1} x^{2}

f (x) = 6 x^{2} - x^{3}, at x = 1

- sin (x) - 4

\int (t) (e^{2 t}) d t

f (x) = cosh (3 \cdot ln (\frac{x}{2}))

\int e^{2 x} cos^{2} (x) d x

What is the solution for xy^'-2y=-2x^2+x-2 ?
The solution for xy^'-2y=-2x^2+x-2 is y=-2x^2ln(x)-x+1+c_{1}x^2