What is the integral from 1 to 4 of 3/x ?

The integral from 1 to 4 of 3/x is 6ln(2)

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integral from 1 to 4 of 3/x

\int_{1}^{4} \frac{3}{x} d x

6 ln (2)

Solution steps

\int_{1}^{4} \frac{3}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{4} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 3 [ln ∣ x ∣]_{1}^{4}

Compute the boundaries:

2 ln (2)

= 3 \cdot 2 ln (2)

Simplify

= 6 ln (2)

\frac{3}{2 s ^{2} + 3 s + 1}

\frac{d y}{d x} = 2 y e^{x + 7}

x \to 1 - lim (3)

\frac{x ^{2}}{x + 1}

\frac{d}{d y} (cos (x) sin (y))

What is the integral from 1 to 4 of 3/x ?
The integral from 1 to 4 of 3/x is 6ln(2)