What is the derivative of e^{4t} ?

The derivative of e^{4t} is e^{4t}*4

What is the first derivative of e^{4t} ?

The first derivative of e^{4t} is e^{4t}*4

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derivative of

e^{4 t}

e^{4 t} \cdot 4

Solution steps

\frac{d}{d t} (e^{4 t})

Apply the chain rule:

e^{4 t} \frac{d}{d t} (4 t)

= e^{4 t} \frac{d}{d t} (4 t)

\frac{d}{d t} (4 t) = 4

= e^{4 t} \cdot 4

\frac{d}{d x} (2 x^{4} + x^{3} + 5 x^{2} - 3 x + 8)

\frac{d}{d x} (x^{2} \cdot e^{- 3 x})

(e^{t} x + 1) d t + (e^{t} - 1) d x = 0, x (1) = 1

x \to 1 lim (lo g_{\frac{1}{e}} (x))

t \cdot e^{5 t} sin (3 t)

What is the derivative of e^{4t} ?
The derivative of e^{4t} is e^{4t}*4
What is the first derivative of e^{4t} ?
The first derivative of e^{4t} is e^{4t}*4