What is the derivative of e^{x^4}+7x ?

The derivative of e^{x^4}+7x is e^{x^4}*4x^3+7

What is the first derivative of e^{x^4}+7x ?

The first derivative of e^{x^4}+7x is e^{x^4}*4x^3+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{x^{4}} + 7 x)

e^{x^{4}} \cdot 4 x^{3} + 7

Solution steps

\frac{d}{d x} (e^{x^{4}} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x^{4}}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (e^{x^{4}}) = e^{x^{4}} \cdot 4 x^{3}

\frac{d}{d x} (7 x) = 7

= e^{x^{4}} \cdot 4 x^{3} + 7

f (x) = x^{2} + 16, at x = 3

\int \frac{e ^{8 x}}{e ^{8 x} + 6} d x

y \to 1 lim (\frac{2 y ^{2} + 3}{y - 1})

\frac{d}{d t} (2 e^{- t} t - e^{- t} t^{2})

f (x) = ln (2 x^{5} (5 x - 1)^{3})

What is the derivative of e^{x^4}+7x ?
The derivative of e^{x^4}+7x is e^{x^4}*4x^3+7
What is the first derivative of e^{x^4}+7x ?
The first derivative of e^{x^4}+7x is e^{x^4}*4x^3+7