What is the tangent of f(x)= 4/x ,\at x=2 ?

The tangent of f(x)= 4/x ,\at x=2 is y=-x+4

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tangent of f(x)= 4/x ,\at x=2

tangent of

f (x) = \frac{4}{x}, at x = 2

y = - x + 4

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{4}{x ^{2}}

Compute the slope of

f (x) = \frac{4}{x}

x = 2 : m = - 1

Find the line with slope m=

- 1

and passing through

(2, 2) : y = - x + 4

y = - x + 4

\int \frac{1}{x ( ln ( x ^{5} ) )} d x

\frac{\partial}{\partial y} (ln (x) + y^{3} x)

\int \frac{2 - x}{x ^{2} + x} d x

\int_{4}^{16} \frac{1}{8 - x} d x

x \to 2 + lim (\frac{8}{x - 2})

What is the tangent of f(x)= 4/x ,\at x=2 ?
The tangent of f(x)= 4/x ,\at x=2 is y=-x+4