What is (\partial)/(\partial y)(3x^2-2xy+2) ?

The answer to (\partial)/(\partial y)(3x^2-2xy+2) is -2x

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(\partial)/(\partial y)(3x^2-2xy+2)

\frac{\partial}{\partial y} (3 x^{2} - 2 x y + 2)

- 2 x

Solution steps

\frac{\partial}{\partial y} (3 x^{2} - 2 x y + 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (2) = 0

= 0 - 2 x + 0

Simplify

= - 2 x

\frac{\partial}{\partial x} (ln (\frac{3 x y}{5 z}))

\int (2 x + 1) x - 5 d x

∣ 4 x - 1 ∣, x^{2} - 5

\frac{d y}{d x} = - (\frac{y ^{2}}{1 + y ^{2}} e^{(- x)})

x \to 4 lim (7)

What is (\partial)/(\partial y)(3x^2-2xy+2) ?
The answer to (\partial)/(\partial y)(3x^2-2xy+2) is -2x